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The reaction of Benzene to m-Nitroacetophenone will be in the presence of CH3COCl, Anhyd.
AlCl3 which will be the Freidel-Craft alkylation and then it will be followed up by HNO3/H2SO4.
First, take Benzene in the presence of CH3COCl, Anhyd.
AlCl3 which will be the Freidel-Craft alkylation to obtain the Benzene with COCH3 compound then heat it in the presence of HNO3/H2SO4 to obtain m-Nitroacetophenone compound.
This Reaction can be easily done in 2 Steps.
For this reaction to Occurs we must need the Benzene to reacts with the Conc. Nitric acid and Sulphuric acid in the presence of the anhydrous Aluminium Chloride.
Final Product formed will be in meta positions of the Benzene.
Reaction to this answer is shown below and the diagrammatically representation is attached below in the attachment.
Step 1. Nitration of the Benzene.
C₆H₆ + HNO₃ ----------- C₆H₅NO₂ + H₂O
Step 2. Reaction with the Acyl Halides.
C₆H₅NO₂ + CH₃COCl ---------- NO₂C₆H₄COCH₃ + HCl
This Product formed is called as the meta - Nitroacetophenone
Hope it helps.
u can say that chemically it is experimental not theoretical or mathmaticall