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question: - how to identify oxidising agent and reducing agent in a chemical equation. explain with logic and also by giving some examples..
needed an easy trick to understand concept.

1 mg is reducing agent and O2 is oxidising agent

1)Fe2O3 is reduced Fe

CO is Oxidised

Fe2O3 is oxidising agent

CO is reducing agent

2)MnO2 is getting reduced...and is oxidising agent

AL is oxidised and is reducing agent

3)H2S is oxidised and is reducing agent

SO2 is reduced and is oxidising agent

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Step-by-step explanation:

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oxidising agent are the substance which is getting reduced

reducing agent are the substance which is ge tting oxidised

eg:

cuo +H2 cu + H2O

here cuo is reduced as removal of oxygen

H2 is oxidized as addition of oxygen

s,H2 is reducing agent

cuo is oxidising agent

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Question:

how to identify oxidising agent and reducing agent with suitable examples?

◆ Redox Reaction = The reaction in which one substance added and another is removed.

● Oxidation Reaction = The reaction in which Oxygen is added and hydrogen is removed is called oxidation.

● Reduction Reaction = The reaction in which hydrogen is added and oxygen is removed is called reduction reaction.

● Oxidising Agent = The reaction in which hydrogen is added and oxygen is remove is called oxidising agent.

● Reducing Agent = The reaction in which Oxygen is added and hydrogen is removed is called reducing agent.

Example:

Reaction of Manganese dioxide with hydrochloric acid involves redox reaction.

MnO2 + 4HCl --- MnCl2 + Cl2 + 2H2O

Oxidising agent/reduction = Cl2

Reducing agent/oxidation = MnCl2

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redox reaction is a reaction in which oxidation and reduction take place simultaneously

here cu is reduced as it loses oxygen whereas h2 is oxidised as it gains oxygen

mate here is yur answer :

chlorine can be converted to chloride ion easily than fluorine to fluoride ion. why?

let's define some terms first. linus pauling defines electronegativity (en) as "the power of an atom to attract electrons to itself." electron affinity (ea) is the work needed in removing an electron from a negative ion (thus the energy gained in reversing the process). the en of f is 3.98, and of cl is 3.16. the ea of f is 328.0 kj/mol, and of cl is 348.8 kj/mol. why is the ea of cl greater than that of f, when the en of f is greater than cl? the answer lies in the fact that f is a smaller atom than cl. when an electron adds to f, the electrons are closer to each other than in cl, so there is stronger electron-electron repulsion. is why chloride formation is easier than fluoride formation.

answer:

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