If a return type of a function is not specified

#include<stdio.h>

#include<conio.h>

#include<stdlib.h>

void main()

{

int i,n,q,l,k,j,*a=NULL;

clrscr();

printf("enter the no of entries: ");

scanf("%d",&n);

a=(int*)calloc(n,sizeof(int));

for(i=0;i<n;i++)

{

scanf("%d",&a[i]);

}

printf("enter the quantity to be consumed\n");

scanf("%d",&q);

for(i=0;i<n;i++)

{

if(a[i]>q)

{

a[i]=a[n-1];

n--;

i--;

}

}

for(i=0;i<n;i++)

{

k=a[i]; //selecting 1st element

for(j=i+1;k+a[j]<q&&j<n;j++)

{

k=k+a[j]; //2nd element decided

for(l=j+1;l<n;l++)

{

if(k+a[l]==q) //checking for 3rd element

{

printf("\tyes\n");

goto end;

}

}

k=k-a[j];

}

k=k-a[i];

}

printf("\tno");

end:getch();

exit(0);

}

answer:

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Explanation:

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answer:

The compareTo() method compares two strings lexicographically. ... The method returns 0 if the string is equal to the other string. A value less than 0 is returned if the string is less than the other string (less characters) and a value greater than 0 if the string is greater than the other string (more characters).

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C-Language: The main function returns "0"

Explanation:

because the main function datatype is "int"

Compare to () method compar two string lexicographically ... The result is a positives integrs if the string object lexicographically follows the argumet string . The result is zero if the strings are equal , compare To retures 0 exactly when the equals (objects) method would return true.

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Explanation:

handwriting the type of function does not return anything

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Return type of math. round ()function in Java is:int

return type

Explanation:

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answer:

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