From the quadratic equation if one root is 3-2√5​

complex roots always occur in pairs.

If one root is a+√ x

then other root will be a-√y

one given root= 3-2√5

other root = 3+2√5

sum of roots= 3-2√5 + 3+2√5

=6

product of roots= (3-2√5)*(3+2√5)

=-9

general formula for writing quadratic equations-

x^2-(sum of roots)x + (product of roots)

therefore, required equation is

x^2-6x-9=0

(ans)

answer:

what type of dramatical question you are writing.

answer:

x-x+6x-p÷p=x-x +6x-0 = 5x