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Step I: Draw the line segment BC = 8 cm and at point B, make an angle of 45°, say ∠XBC. Step II: Cut the line segment BD = 3.5 cm (equal to AB − AC) on ray BX. Step III: Join DC and draw the perpendicular bisector PQ of DC. Step IV: Let it intersect BX at point A.
I I hope it will help you
With B as center draw an arc cutting at O. now with O as center of same radius draw arc cutting at D join BD and extend till meet AF at C
you for asking question. here is your answer:
6y - 12 = (x-4)² - 2/3
6y - 12 = x² - 8x + 46/3
6y = x² - 8x + 82/3
now we will divide each term by 6.
y = x²/6 - 4x/3 + 41/9
x = y²/6 - 4y/3 + 41/9
now we will solve for y.
12 + √6(-17+9x)/3 , 12- √6(-17+9x)/3
f^-1(x) = 12+√6(-17+9x)/3 , 12 -√6(-17+9x)/3