Solve the following given equations in x and y: -

1)3x+2y=11

2x+3y=4

2) 8x+5y=9

3x+2y=4

3) 217x+131y=913

131x+217y=827

1)3x +2y =11==1eq

2x + 3y =4 ===2eq

By elimination method :-

(3x +2y=11) ×2

(2x+3y=4)×3

6x +6y=22

6x+9y=12

- - -

-3y = 10

y =-10/3

.

put y in 1 st eq

=》3x +2(-10/3)=11

=》9x -20=33

=》9x=33+20

=》9x=50

x=50/9

▪X=50/9 and y =-10/3 ans

2)8x+5y=9 ===1eq

3x+2y=42eq

By elimination method

(8x+5y=9 )×3

(3x+2y=4)×8

24x+15y=27

24x+16y=32

_ _ _

-y= -5 , y =5

put y in 1 st equation

8x+5(5)=9

=》8x +25=9

=》8x=9 -25

=》8x=-16

=》x=-2

▪y=5 and x =-2 ans

3)217x+131y=913===1 eq

131x+217y=8272eq

By elimination method

(217x+131y=913)×131

(131x+217y=827)×217

=》28427x+17161 y= 119603

28427 x +47089y =179459

_ _ _

-29928 y = -59856

y = 59856/29928

Y =2

put value of y in eq 1

=》217x+131(2)=913

=》 217x + 262 =913

=》217x=913 -262

=》217x=651

=》x=651/217

=》x=3

▪x=3 and y = 2 answer

3x+2y= 11 -(1)

2x+3y=4 -(2)

By eliminating y from the above equations. The coefficients of y in the given equations are 2 and 3 respectively. The L.C.M of 2 and 3 is 6. So,we need to make the coefficients equal to 6 in both the equations.

Multiplying equation -(1)by 3 and equation -(2) by 2, we get:

9x+6y=33 -(3)

4x+6y=8 -(4)

Subtracting -(4) from -(3),we get:

5x= 25

⟹x=5

Substituting in equation -(1),we get:

15+2y= 11

⟹2y= -4

⟹y= -2

8x+5y= 9 -(1)

3x+2y= 4 -(2)

Let's eliminate x from the given equations. The coefficients of x in the given equations are 8 and 3 respectively. The L.CM of 8 and 3 is 24. So, we need to make the coefficients equal to 24.

Multiplying both sides of equation -(1)by 3 and equation -(2) by 8, we get:

24x+15y= 27 -(3)

24x+ 16y= 32 -(4)

Subtracting -(4)from -(3), we get:

-y= -5

⟹ y= -5

Putting y=5 in -(1),we get:

8x+25= 9

8x= -16

x= -2

217x+131y= 913 -(1)

131x+217y= 827 -(2)

Adding equations -(1)and -(2),we get:

348x+348y= 1740

⟹ x+y= 5 -(3)

Subtracting equation -(2) from -(1),we get:

86x-86y= 86

86x-86y= 86⟹x-y= 1 -(4)

Adding equation -(3) and -(4),we get:

2x= 6

⟹x= 3

Putting x= 3, in equation -(3), we get y= 2

.......................

first add and subtact both equations.

we get result,

x+y=5

x-y=1

by applying elimination method

x=3

y=2

From Ist equation we get,

x=(913-131y)/217

Substituting x in 2nd equation we get,131{913-131y)/217} + 217y =827

(119603-17161y)/217 +217 y =827

Taking LCM,

119603-17161y+47089y = 827*217

119603+29928y = 179459

29928y=179459-119603

29928y = 59856

y=59856/29928

y=2

Putting y=2 in 1st equation,we get

217x +262=913

217x = 913-262

217x = 651

x = 651/217

x = 3

Therefore, x=3 and y=2

Here is your answer ,

Solution :-

On Adding equation (I) and (ii) , we get :-

On substracting equation ii from I , we get :-

On Solving equation (iii) and (IV) , we get ;

Putting value of y in equation(IV) ,we get ;

Hope it helps you :)

here is your answer

I hope it will help u

HEY MATE HERE IS YOUR ANSWER .....IF IT HELPS YOU THEN PLEASE MARK AS BRAINLIEST

THANKYOU.....

AND FOLLOW ME SUCH THAT I CAN ANSWER ALL YOUR QUESTIONS...

on adding both equation we get

348x + 348y =1740

Divide the whole equation by 348, we get

x+y =5

Multiply this equation by 217 we get

217x+217y=1085

Now subtract this equation from 217x+131y=913 we get

86y=172

so y=2 and x =3

Step-by-step explanation:

answer:

xd mere

i also i love my following nd followers

answer:

143041 is the mark me as a brainlist