In an equilateral that the square of one side is equal to four times the square of one of its altitudes​

ho mate

here is your answer

Let ABC be equilateral triangle.

Let AD be perpendicular bisector from A on to BC. So BD = CD = 1/2 BC

ADC is a right angle triangle. So  AC² = AD² + DC²

AC² = AD² + (1/2 AC)²           

    AD² = 3/4 AC²  

     4 AD² = 3 AC²

mark as brainlest

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