The diameter of the circle is 52 cm and the length of one of its chord is 20 cm. find the distance of the chord from
the center​

d=Vr^2-(C/2) 2

= v26 ^2-10^2 =v676-100=v576

= 24cm

distance of the chord from the centre is 24cm

Step-by-step explanation:

Since we have given that

Diameter of circle = 52 cm

So, Radius =

Length of one of its chord = 20 cm

So, distance of the chord from the center would be

Hence, the distance of the chord from the center is 24 cm.

# learn more:

Diameter of a circle is 26 CM. and length of a chord of the circle is 24 CM. Find the distance of the chord from the center

given statement is "three minus the product of two and a number x "

we need to write mathematical expression for the given statement. that can be easily done by breaking the given statement into smaller pieces.

"product of two and a number x" means multiply 2 and x so that can be written as 2x

now "three minus the product of two and a number x " means subtract 2x from 3

so we get "3-2x"

hence final expression will be (3-2x).

answer:

very simple it is

step-by-step explanation:

combine both u will get a formulae that is a2_b2_c2 it is square and solve ncert right 2nd chapter polynomials hahahhahha i will ask another question learn splitting middle term hope u