tan(x y) = (tan x tan y) / (1 tan x tan y)
sin(2x) = 2 sin x cos x
cos(2x) = cos^2(x) - sin^2(x) = 2 cos^2(x) - 1 = 1 - 2 sin^2(x)
tan(2x) = 2 tan(x) / (1 - tan^2(x))
sin^2(x) = 1/2 - 1/2 cos(2x)
cos^2(x) = 1/2 + 1/2 cos(2x)
sin x - sin y = 2 sin( (x - y)/2 ) cos( (x + y)/2 )
cos x - cos y = -2 sin( (x - y)/2 ) sin( (x + y)/2 )
a/sin(A) = b/sin(B) = c/sin(C) (Law of Sines)
(a - b)/(a + b) = tan [(A-B)/2] / tan [(A+B)/2] (Law of Tangents)
2 over 5 is the correct option which lets grace find the x-coordinate for point c.
to find: the fraction to find the x-coordinate for point c.
given the endpoints are a = (3,2) b = (6,11)
ratio is given as ac: bc = 2: 3
total number of units for the entire line ab = sum of ratio = 2+3 = 5.
to obtain c, taking ac, we get
x coordinate of c = value taken from the ratio / sum of ratio = 2/5.
hence, the correct option is 2 over 5.
is your questions' answer
sino - cose then
a tano & cose o....