If sina : sinb : sinc = 3: 4: 5 then tana/2
: tanb/2: tanc/2
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2/3

Step-by-step explanation:

tan A = 4/5x5/3

=4/3 =2/3

2/3

Step-by-step explanation:

4/3

Step-by-step explanation:

hope its help you my friend

sinA=-4/5 sin^2A+cos^2A=1 cos^2A=1-sin^A=1-(-4/5)^2 cos^2A=1-(16/25) cos^2A=9/25 cosA=3/5 tanA=sinA/cosA tanA=(-4/5)×(5/3) =-4/3 tanA=-4/3

Step-by-step explanation:

Hope it will help you.....

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Step-by-step explanation:

we know that sin 2x = 2tanx / 1 + tan²x

put x/2 instead of x ( it should be valid for any number,  be it x or a or b or x/2)

so sin x = 2 tan x/2  / 1 + tan²x/2

put tan²(x/2) as m

then :

-4/5 = 2m / 1 + m²

solve a quadratic :

4m² + 10m + 4 = 0

m = [ -10 ± sqrt ( 100 - 4 x 4 x 4 ) ] / 2 x 4

on solving we get : m = -0.5 or -2.

that makes tan²x/2 = 0.25 or 4.

thats your answer

answer:

6

step-by-step explanation:

given statement is "three minus the product of two and a number x "

we need to write mathematical expression for the given statement. that can be easily done by breaking the given statement into smaller pieces.

"product of two and a number x" means multiply 2 and x so that can be written as 2x

now "three minus the product of two and a number x " means subtract 2x from 3

so we get "3-2x"

hence final expression will be (3-2x).