tan A = 4/5x5/3
hope its help you my friend
sinA=-4/5 sin^2A+cos^2A=1 cos^2A=1-sin^A=1-(-4/5)^2 cos^2A=1-(16/25) cos^2A=9/25 cosA=3/5 tanA=sinA/cosA tanA=(-4/5)×(5/3) =-4/3 tanA=-4/3
Hope it will help you.....
Plzz mark it brainliest
we know that sin 2x = 2tanx / 1 + tan²x
put x/2 instead of x ( it should be valid for any number, be it x or a or b or x/2)
so sin x = 2 tan x/2 / 1 + tan²x/2
put tan²(x/2) as m
-4/5 = 2m / 1 + m²
solve a quadratic :
4m² + 10m + 4 = 0
m = [ -10 ± sqrt ( 100 - 4 x 4 x 4 ) ] / 2 x 4
on solving we get : m = -0.5 or -2.
that makes tan²x/2 = 0.25 or 4.
thats your answer
Aisa marunga ki Thera oothega hi nahi
given statement is "three minus the product of two and a number x "
we need to write mathematical expression for the given statement. that can be easily done by breaking the given statement into smaller pieces.
"product of two and a number x" means multiply 2 and x so that can be written as 2x
now "three minus the product of two and a number x " means subtract 2x from 3
so we get "3-2x"
hence final expression will be (3-2x).
: tanb/2: tanc/2