Cost price of an article for a shopkeeper is rs. 3000.shopkeeper marked its as rs. 4000.he allows some discount on the marked price still gains 20 %. what percent discount dose he allow to the customer?

Given,
CP=Rs.3000
MP=Rs.4000
SP required to gain 20% = Rs.3600
so discount given = MP - SP
=Rs(4000 - 3600)
=Rs400
Discount percentage = Discount given/ MP*100
》Rs400/Rs4000*100
= 10 %
so the shopkeeper gave 10% discount to customer.
HOPE IT HELPS YOU.

3000*20/100=600 gain percentage
4000*10/100=400 given discount

Step-by-step explanation:

Cp = 3000, mp = 4000, mp_cp = 1000, 20% of cp = 20×3000/100 = 600, D = 1000_600 = 400 Now, 400×100/4000 =10 Discount% = 10%..

Cp=3000
mp=4000
profit=4000-3000=1000
let dis be x
atq
4000x=20/100×4000
x =1/5%

Cp=3000
mrp=4000
profit %=20

sp=3000*120/100=3600

so discount =4000-3600=400

discount %=400/4000*100 =10% 
this is your answer hope it will in case of any doubt comment  below

Profit _ 20% of 3000 =600
sp = 3600
mp =4000
dicount =400 rs
=10% of 4000
ans =10%

This is ur answer hope it will help u in case of any doubt comment below

Q:

if a number 72k23l is divisible by 88. then find value of k and l ?

a)  k=8 & l=2
b)  k=7 & l=2
c)  k=8 & l=3
d)  k=7 & l=1

answer:     b) k=7 & l=2 

explanation:

if a number to be divisile by 88, it should be divisible by both "8" and "11"
check for '8' :
for a number to be divisible by "8", the last 3-digit should be divisible by "8"
here 72k23i --> last 3-digit is '23i'
so i=2 [ (i.e) 232 is absolutely divisible by "8"]
chech for '11' :
for a number to be divisible by "11" , sum of odd digits - sum of even digits should be divisible by "11"
(7 + k + 3) - (2 + 2 + i)
(7 + k + 3) - (2 + 2 + 2)
(10 + k) - 6 should be divisible by "11"
for k = 7
=> 17 - 6 = 11 [ is absolutely divisible by "11"]
so k = 7 , i = 2.

answer:

i can't understand what are you trying to say