The sum of the opposite angles of a cyclic quadrilateral are equal to 180degrees
and sum of opp. sides of cyclic quad. is 180degree..
3. 180 degree.
3. 180 degree
hope it's helpful for you
did chess played by me
I think it is correct
I don't no AAP chess ka saath play karo ya chess apka athletic baat to ask he ha
THEREFORE,. BC=AB=AC (being the radii)
hence in ∆ABC,
it is an equilateral triangle hence angle A=B=C=60°
now as it is quite visible that BS is a diameter, Therefore Angle BAS=180°
i don't know but i will
⏩follow krke jaio⏩radhe radhe