final ans is opt. a
1.Area of quad circle a1=3.14*8²/4
2.Area of triangle a2=1/2(8*8)
3.So area of shaded regions =2(a1-a2)
the abc cm of square of sides are same
Area of square is 16cm^2 we can use the formula of rhombus to calculate the area of the square because all square are rhombus but rhombus are not square.
In the given figure, ABCD is a square with side 8 cm.
It has semi-circles drawn with its sides as diameter.
The area of the shaded region.
Area of shaded region = Area of square - Area of 2 semi circles
= a² - πr²/2
= 8² - 22/7 × (8/2)²/2
= 64 - 22/7 × 4²/2
= 64 - 22/7 × 8
= 64 - 25.14
= 38.86 cm²
Therefore, the area of shaded region is 38.86 cm²
Side of square ABCD,
= 8 cm
Radius of adjoining figures,
= 8 cm
The Area of shaded region = ?
As we know,
The Area of quad circle,
On putting the values, we get
The Area of a triangle,
The Area of shaded region,
So that the shaded region's area will be "36.48 cm²".
Hope it helps you
Pls mark me as the brainliest
see this photo for proper explanation
1) find the full area shaded 14×14=
2) find the the area of semi circle which you should know the arc lenght
how we have to construct it? ☹️
but triangle is possible ☺️