Math, 18.10.2019 11:00, dasmithu1947

Use the factor theorem to show that x-a is a factor of

Answers: 1

Get

Answers

The correct answer was given: sarah050

Factor of which equation plz tell

The correct answer was given: shashidarshanbiradar

$\italic{mark\:as\:brainlist}$
Use factor theorem to show that (x+2) and (2x-3) are factor of (2x³+x-6)

The correct answer was given: Mannubhalla93

1. x-2=0

x=2

Step-by-step explanation:

now, put the value

x-3x+4x-4

2-3(2)+4(2)-4

2-6+8-4

10-10

2. x-3=0

x=3

now, put the value

x-3x+x-3

3-3(3)+3-3

3-9+3-3

12-12

The correct answer was given: helper6462

mark me as brainliest

Step-by-step explanation:

=x4+ 2X³-2X²+2x - 3

= x4 + 2x³-2x²+2x-3 / ( x+3 )

= x³ - x²- x +1

= (x³-x²-x+1 ) ( x+3 )

= { x²( x-1) -1 ( x- 1 ) ( x+3 ) }

= (x²-1) (x-1) (x+3 )

The correct answer was given: Firdaus17f

Step-by-step explanation:

let (x-3)=0

therefore x=3

putting the value of x=3 in the following polynomial

((3×3×3)-(3×3×3)+(4×3)-12)

(27-27+12-12)

(0+0)=0

as by putting the value of x=3 the following polynomial doesn't leave any remainder.

therefore, (x-3) is a factor

The correct answer was given: Simrankanojia

using factor theorem

x-2=0

=x=2

Put value of x = 2

${2}^{3} - 2 - 6 \\ = 0 \\ therefore \: 2 \: is \: the \: root \: of \: p(x). \\ thus \: x - 2 \: is \: a \: factor \: of \: p(x)$

Using factor theorem

(x+2)(x-1)=0

$using \: identity \: (x + a)(x + b) = {x}^{2} + (a + b)x + ab \\ \\ = {x}^{2} + (2 - 1)x - 2 = 0 \\ {x}^{2} + x - 2 = 0 \\ {x}^{2} + x = 2 \\ x(x + 1) = 2$

after this it is a little tough to express it using these formulae writing as its hard to type each and every thing in detail and as it is midnight in india I can't just express it on a piece of paper but if you make some effort you will be successful

The correct answer was given: ravichandrareddybuss

X+2 is a factor

Therefore x=-2

Putting value of x

The equation is equal to zero

2x-3 is factor

Then x=3÷2

Putting value of x

The equation is equal to zero

Hence these are factors

The correct answer was given: shad007

By using factor theorem,

if the( x+2) are the factor of the polynomial then ,

X+2=0

X= -2

therefore

p(x)= X^4+X^3+2x^2+ 4x-8

X = -2 taking

p(-2) = (-2)^4+(-2)^3+2(-2)^2+4(-2)-8

= 16+(-8)+2(4)-8-8

= 16+(-8)+8-8-8

= 8+8-8-8

=16-8-8

= 8-8

= 0
Therefore (X+2) are the factor of the given polynomial.

Similarly you can solve another one.

The correct answer was given: vijayrockzz4949

Given polynomial p(x) = x³ - 3x² +4x - 12
If x-3 is a factor of p(x) then... p(3) =0
p(3) = 3³ - 3(3)² +4(3) - 12
= 27 - 27 + 12 - 12
= 0
So p(3) = 0.
Hence, x-3 is a factor of p(x).

The correct answer was given: jivan99

Let g(x)=x-3
g(x)=0
x=3
Putting the value of x in the equation
3³-3(3²)+4(3)-12=0
27-3(9)+12-12=0
27-27+12-12=0
0=0

The correct answer was given: Brain

answer:

don't know

The correct answer was given: Brain

answer:

what is means of your