Use the factor theorem to show that x-a is a factor of

Factor of which equation plz tell

1. x-2=0

x=2

Step-by-step explanation:

now, put the value

x-3x+4x-4

2-3(2)+4(2)-4

2-6+8-4

10-10

=0

2. x-3=0

x=3

now, put the value

x-3x+x-3

3-3(3)+3-3

3-9+3-3

12-12

0

mark me as brainliest

Step-by-step explanation:

=x4+ 2X³-2X²+2x - 3

= x4 + 2x³-2x²+2x-3 / ( x+3 )

= x³ - x²- x +1

= (x³-x²-x+1 ) ( x+3 )

= { x²( x-1) -1 ( x- 1 ) ( x+3 ) }

= (x²-1) (x-1) (x+3 )

Step-by-step explanation:

let (x-3)=0

therefore x=3

putting the value of x=3 in the following polynomial

((3×3×3)-(3×3×3)+(4×3)-12)

(27-27+12-12)

(0+0)=0

as by putting the value of x=3 the following polynomial doesn't leave any remainder.

therefore, (x-3) is a factor

using factor theorem

x-2=0

=x=2

Put value of x = 2

II

Using factor theorem

(x+2)(x-1)=0

after this it is a little tough to express it using these formulae writing as its hard to type each and every thing in detail and as it is midnight in india I can't just express it on a piece of paper but if you make some effort you will be successful

X+2 is a factor

Therefore x=-2

Putting value of x

The equation is equal to zero

2x-3 is factor

Then x=3÷2

Putting value of x

The equation is equal to zero

Hence these are factors