16 is the answer I got.
AB = XY
C is the mid-point of line segment AB, AB = 2AC.
Also,D is the mid-point of line segment XY.
XY = 2XD
XY = 2AC (∵ XD = AC).
By Euclid's sixth axiom, things we are doubles of same thing are equal to one another, we have
AB = XY.
Hope it helps!
ca is write answer ok you don't know
as given C is the mid point of AB and D is the mid point of AC therefore
AC = 1/2AB(1)
AD = 1/2AC(2)
multiply equation one and two we get,
AC into AD = 1/2AB into 1/2AC
AC into AD =1/4AB into AC
(AC gets cancled on both sides)
AD = 1/4AB
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Hi. Hope this will help you .
C is the midpoint of AB.
D is the midpoint of XY.
*Because things which are double of same thing are to one another.
I don't know correct answer
I guess this is your question: If AB is a line and C is the mid-point of AB and D is mid-point of AC then prove that AD=¼AB
AC = CB (as C is the mid-point of line segment AB)
Add AC to both sides, we get
AC + AC = AC + CB ( If equals are added to equals, then the wholes are equal)
So, 2 AC = AB (as AC+CB = AB)
AC = AB/2 (1)
Next, AD = DC (as D is the mid-point of AC)
Add AD to both sides, we get
AD + AD = AD + DC (If equals are added to equals, the wholes are equal)
2 AD = AC (as AD + DC = AC)
Therefore, AD = AC÷2 (2)
Substituting value of AC from (1) in (2), we get
AD = AB/2÷ 2
AD = AB/2 x ½
AD = ¼AB
Hope you've understood!
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