Find the value k for the quadratic equation 2x^2 + kx + 3 so have two equal roots.

hey mate, here is ur answer

Let a = 2, b = k, and c = 4 in the quadratic formula
x=−b±b2−4ac−−−−−−−√2a.x=−b±b2−4ac2a.
x=−k±k2−4(2)(4)−−−−−−−−−−√2(2)x=−k±k2−4(2)(4)2(2)
=−k±k2−32−−−−−−√4=−k±k2−324
=−k4±14k2−32−−−−−−√.=−k4±14k2−32.
For xx to be real, must have
k2−32≥0.k2−32≥0.
Solving the equation k2−32=0k2−32=0, get that k2=32⟹k=±32−−√k2=32⟹k=±32
=±16(2)−−−−

Value of k should be

Your answer is 17.44133 or 17.45

answer:

1.297

2.306

3.2,994

step-by-step explanation:

question are solution