∴The coordinate of the point is
Given points of plane are (1,2,3) ,(4,2,-3) and (0,4,3).
Therefore the equation of plane
⇒12x -12 - 42y+84 +6z-18=0
⇒12x - 42y +6z +54= 0
⇒2x-7y +z +9 =0
The equation of straight line is
Any point on the straight line be P (r+3,-r-4,-6r-5).
Let p be lie on the plane. So p will be satisfy the equation of plane.
∴ The coordinate of p =
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