Distance(x) travelled by a particle depends on time t as x=alpha. t+beta. the dimension of alpha/beta is?

the dimensions will be T^-1

Dimensions of force are  MLT^-2

Considering the equation,

α  -  t²/βv²

So,alpha should also have the same dimension 

α = MLT^-2

Dimension of 

t=T

v= LT^-1

So,

t²/v² = L^-2 T^4

So,

t²/βv²= MLT^-2

So,

β=M^-1  L^-3 T^6

Now,

α/β = M^2 L^4 T^-8

This will be the dimension of α/β

Hope it helps..... The answer should be ML^3T^-4

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is it too easy but I need time for wait I'll answer

same dimensions can be add subtract multiply and divide but different dimensions can only multiply and divide.

you don't write the equation so how can we give the answer

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