An object 5.0 centimetre centimetre in length is placed at a a distance of 20 cm in front of convex mirror radius offer radius of a curvature 30cm find the position of the image its nature and size

beyond the centre of curvature and is extended/ enlarged

Explanation:

If like it pls brain list it

Height of object=5cm

f=15 cm

u=-20cm

therefore,

1/v=1/f-1/u

=1/15+1/20

=7/60

so v =60/7

therefore height of image=60/7/20=3/7

so the image is virtual,erect and smaller in size by 3/7th of its original size

answer:

answer:

sorry yar i dont know the answer of question