Aball is thrown with velocity of 39.2 m/s at an angle 30° with the horizontal. calculate the maximum height, time of flight and horizontal range of the projectile

answer written in picture

answer:

b

Explanation:

What is a projectile? Derive the expression for the trajectory, maximum height, time of flight, and horizontal range for a projectile thrown upwards, making an angle Ɵ with th

answer:

take out ratio of both and compare the maximum hight

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answer:

The range (R) of the projectile is the horizontal distance it travels during the motion. Using this equation vertically, we have that a = -g (the acceleration due to gravity) and the initial velocity in the vertical direction is usina (by resolving). Hence: y = utsina - ½ gt2 (1)

answer:

Time of flight of projectile is given by formula,

T = (2 × u × sin(theta))/g

Where u is initial velocity, g is acceleration due to gravity, and theta is angle made by initial velocity with horizontal.

Given in the problem, theta = 30 degree, initial velocity is 19.6 m/s and g =9.8 m/s^2.

T = (2 × 19.6 × (1/2))/9.8

T = 19.6/9.8 = 2

T = 2 seconds.

Hope this will help

Definition :the motion of a particle due to a initial velocity which was given to it initially without any propulsion

Derivation :

Initial velocity u and with angle ¤

The velocity of projectile is u which makes¤ with horizontal

Vertical component of the initial velocity uy = usin¤

Horizontal component of the initial velocity ux = ucos ¤

Let , T be the time of flight .so the max height is reached at T/2

The vertical component became 0 at the maximum height H

Using

V = u+at

0 =uy -gt 0 = uy -gt

t= usin¤/g=T/2

T= 2usin¤/g

For height

S= ut+1/2at^2

H=uyT/2-1/2g(T/2)^2

H= usin¤*usin¤/g-1/2g*u^2sin^2¤/g^2

H=u^2sin^2¤/2g

For range

R=yxT

R=ucos¤*2usin¤/g

R=u^2sin2¤/g

Explanation:

Because honey has more strong intermolecular attractive forces than water.so the particles are strongly binded in honey than water.hence honey is more viscous than water. 1. According to chemistry- because the inter molecular force between the molecules of honey is strong so it is more visous then water.

Explanation:

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Explanation:

Resolving in the vertical direction

↑

⏐

⏐

+

The initial velocity is

u

0

=

392

sin

(

1

6

π

)

m

s

−

1

Applying the equation of motion

v

2

=

u

2

+

2

a

s

At the greatest height,

v

=

0

m

s

−

1

The acceleration due to gravity is

a

=

−

g

=

−

9.8

m

s

−

2

Therefore,

The greatest height is

h

y

=

s

=

0

−

(

392

sin

(

1

6

π

)

)

2

−

2

g

h

y

=

(

392

sin

(

1

6

π

)

)

2

2

g

=

1960

m

The time to reach the greatest height is

=

t

s

Applying the equation of motion

v

=

u

+

a

t

=

u

−

g

t

The time is

t

=

v

−

u

−

g

=

0

−

392

sin

(

1

6

π

)

−

9.8

=

20

s

The total time of flight is

=

40

s

Resolving in the horizontal direction

→

+

The velocity is constant and

u

x

=

392

cos

(

1

6

π

)

The range in the horizontal direction is

s

x

=

u

x

⋅

t

=

392

cos

(

1

6

π

)

⋅

2

⋅

20

=

13579.3

m

graph{-(19.6/(3*392^2))x^2+(1/sqrt3)x [-293, 14340, -2480, 4844]}

answer:

nice dp

(i) state the function of the fixed pulley p2.

(ii) if the free end of the string moves through a distance x, find the distance by the load w is raised.

(iii) calculate the force to be applied at c to just raise the load w = 20 kgf, neglecting the weight of the pulley p1 and friction.