tell i give answer
The time period of a pendulum is given by,
and we also know that,
=> Δt= /(αΔT)
=> Δt₁/Δt₂= ΔT₁/ΔT₂
=> 12/4= (40-T)/(T-20)
=>3T- 60= 40- T
=> T= 25°
then are equal
(v1t1 + v2t2)/(t1 + t2)
the particle moved from p to q with a velocity of v1 let t1 be the time taken.
thus the displacement will be v1t1.
similarly from q to p the displacement will be v2t2
thus avg. velocity will be (v1t1 + v2t2)/(t1+t2)