Calculate the number of photons emitted in 10 hours by a 60 watt sodium lamp wavelength of photon = 5839 angstrom

Watt = Energy/Time = Joule/sec

Total energy = 60×10×3600J

let the no. of photons be Z

then,

60×10×3600J = Z { 12420/5893 } × 1.6 × 10^(-9)

by solving,

Z = 6.4 × 10^(24) answer!

Energy of photon, E = hν = h(c/λ) = 3.374 x 10-19 J

[It is known that, h = 6.626 x 10-34 m2 kg/s and c = 3 x 108 m/s]

Number of photons emitted by the sodium lamp in one second = [60 / 3.374 x 10-19]

∴ The number of photons emitted by the sodium lamp in 10 hours is

= [(60 x 10 x 3600)/ (3.374 x 10-19)] = 6.4 x 1024

Energy of photon, E = hν = h(c/λ) = 3.374 x 10-19 J

[It is known that, h = 6.626 x 10-34 m2 kg/s and c = 3 x 108 m/s]

Number of photons emitted by the sodium lamp in one second = [60 / 3.374 x 10-19]

∴ The number of photons emitted by the sodium lamp in 10 hours is

= [(60 x 10 x 3600)/ (3.374 x 10-19)] = 6.4 x 1024

Energy of photon=hv=3.374×10^-19J No.of photons emitted by sodium lamp in 10 hours=60×10×3600/3.374×10^-29= =6.4×10^24

Here is the answer to your question:

Energy of photon, E = hν = h(c/λ) = 3.374 x 10-19 J

[It is known that, h = 6.626 x 10-34 m2 kg/s and c = 3 x 108 m/s]

Number of photons emitted by the sodium lamp in one second = [60 / 3.374 x 10-19]

∴ The number of photons emitted by the sodium lamp in 10 hours is

= [(60 x 10 x 3600)/ (3.374 x 10-19)] = 6.4 x 1024

So, n=

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