An object of mass 1.5kg travelling in a straight line with a velocity of 5m/s collides with a wooden block of mass 5kg resting on the floor. object sticks with the wooden block after collision and both move together in a straight line. calculate:
(a)the total momentum before collision.
(b) total momentum after collision
(c) the velocity of the combination of these objects after collision
"Mass of the moving object, m1 = 1.5 kg and its initial velocity, u1 = 5 m/s.
Mass of the wooden block, m2 = 5 kg, and its initial velocity, u2 = 0 m/s.
We need to find total momentum before and after the collision of both objects. Therefore m1u1 + m2u2 = m1v1 + m2v2 => v = 1.15 m/s
Before collision, total momentum 7.5 kgm/s and after collision 7.47 kgm/s."
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the momentum of the smaller object is 1.5×5=7.5 kg m/s
And the kinetic energy possesed by it will be;
Energy required to move the greater mass object =its mass = 5 Joules.
So the energy waisted by the smaller mass = 5x as the greater mass will occupy some speed x also, So, the lost energy by the smaller will be=5x Joules
The energy left with the smaller mass= (18.75-5x) Joules.
And so the momentum of the smaller mass we will calculate by using the formula p=√2mK
⇒√(2×1.5×(18.75-5x)) kg m/sec
And so the momentum acquired by the bigger mass will be p=√(10×5x) Joules>
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