where G is gravitational field intensity ,
V is gravitational potential,
and dr is position vector.
given, V = -(x + y + z)
we have to use partial derivatives concepts
similarly, we can get,
Explanation: I hope its answer help to u....
(B) 13 N/kg
1) We have,
Gravitational Potential in a region ,
Hence, Gravitational field is constant.
It is same at all points.
Hence, Magnitude of Gravitational Field
and proceed as done in the step above..
Gravitational intensity =−∂V∂xiˆ−∂V∂yjˆ−∂V∂zkˆ here V=−xyz (assuming that these are product ) Gravitational intensity=yziˆ+zxjˆ+xykˆat point (2,2,2)=4(iˆ+jˆ+kˆ) N/kgGravitational intensity =-∂V∂xi^-∂V∂yj^-∂V∂zk^ here V=-xyz (assuming that these are product ) Gravitational intensity=yzi^+zxj^+xyk^at point (2,2,2)=4(i^+j^+k^) N/kg
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hi dear.. I hope it will helps you
sorry i don't know the answer I just just want points my true statement and i, am just 11 so yeah
The gravitational potential in a region is given by, V = 20(x + y) J/kg. Find the magnitude of the gravitational force on a particle of mass 0.5 kg placed at the origin.
I hope this will help you
If not then comment me
The magnitude of the gravitational force on a particle of mass 0.5 kg placed at the orgin is :
• Given : V = 200(X + Y) J/kg and mass, m = 0.5 kg
• We know that the relation between electric field and potential is given as,
E = - [ (∂V/∂X)i + (∂V/∂Y)j + (∂V/∂Z)k ]
E = - [ (∂200X/∂X)i + (∂200Y/∂Y)j ] N/kg
E = (200i + 200j) N/kg
• Force, F = mE
F = 0.5×( 200i + 200j )
= ( 100i + 100j ) N
• Magnitude of gravitational force is,
|F| = √(100^2 + 100^2)
• |F| = 100√2 N
velocity v = 28 m/s
= 2.8 sec
we know h = 1/2( g* (t* t) )
let t = 2.8 sec
h = 1/2 (10 ) ( 2.8 ²)
h = 39.2 m
sorry..i dont know