It is given that, a stone dropped from a tree takes 2 seconds to reach the ground. We need to find its velocity on striking the ground. Initially, the stone is at rest such that its initial velocity is 0. It will move downward under the action of gravity. Let v is the velocity on striking the ground. using first equation of motion.
Here, a = g and u = 0
So, the velocity of the stone on striking the ground is 19.6 m/s.
A stone dropped from a tree takes 2 seconds to reach the ground. Find its velocity on striking the ground ?
V=0+(10)2 (u=0 because the stone
Is dropped due to
which initial velocity
will be 0)
v = u + at
here, u = 0, and a = g = 9.8 m/s.
So, v = 0 + (9.8)(2)
i .e. v = 19.6 m/ s
v = 0 + (9.8 m/s² × 3 s)
v = 29.4 m/s
∴ Velocity of stone when it strikes the ground is 29.4 m/s
➡️momentum is defined as the effect produced by force.
➡️it is the product of mass and velocity.
➡️it is a vector quantity contains ➡️magnitude as well as direction.
➡️it can also be defined as mass in motion.