S= 20* 2.5 + 1/2 2* 12.5
= 5 + 12.5
= 17.5 m
We have to find "s",that is,distance.
So we will use the formula= v^2-u^2=2as
Distance, d = 56.25 m
It is given that,
Initial velocity of train, u = 20 m/s
Final velocity of train, v = 25 m/s
Acceleration of the train, a = 2 m/s²
We have to find the distance covered by the train. It can be calculated using third equation of motion. It is given as :
x is the distance covered by the train.
x = 56.25 m
Hence, the distance covered by the train is 56.25 m
here V=25,U=20 and a=2
by substituting, we get
hence the distance covered is 225/4
where you telling us the answer ?