I = 2
Resistances R1 = 10, R2= 6R3=8 are connected in series.
So the current flowing in each resistance, If the potential difference is 12V is calculated as follows.
It is the sum of the three resistance R1, R2 and R3 which id 10 + 6 + 8 = 24 ohm.
R1 = 10 ohm
R2 = 6 ohm
R3 = 8 ohm
Total resistance, R = R1 + R2 + R3 = 10+6+8 = 24 ohm
Potential difference = 12 V
Current through circuit = V/R = 12/24 = 0.5A
In series, current through each resistor remains same. So current through each resistor is 0.5 A
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