Two bulbs having rating 100w,220v and 60w,220v one has greater resistance

We know that power = voltage^2 ÷resistance

Therfore r1 = 220^2÷100= 484ohm

And r2 =220^2÷60=806.7ohm .so 2nd one s greater resistance.

Hope it helps

Explanation:

Given :-

Two bulbs have rating 100W, 220V and  60W, 220V.

To Find :-

Which one has the greatest  resistance.

Formula to be used :-

P = V²/R

Solution :-

Putting all the values, we get

For Bulb A

⇒ 100 = (220×220)/R₁

⇒ R₁ = 484 ohm

For Bulb B

⇒ 60 = (220 × 220)/R₂

⇒ R₂  = 806.6 ohm

Hence, bulb B having 60W, 220V will have greater resistance.

Terms to be known :-

P is power in Watt (W) .

R is resistance in ohm .

V is voltage in volts (V) .

answer:

hwy.

explanation: